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Q. $64$ identical drops of mercury are charged simultaneously to the same potential of $10$ volt. Assuming the drops to be spherical, if all the charged drops are made to combine to form one large drop, then its potential will be

Electrostatic Potential and Capacitance

Solution:

$V=\frac{(64 q)}{4 \pi \varepsilon_{0} R}=\frac{64 q}{4 \pi \varepsilon_{0}(4 r)}$
$=16\left(\frac{q}{4 \pi \varepsilon_{0} r}\right)=16 \times 10=160 \,V$