Question

$600\, mL$ of $0.01\, M\, HCl$ is mixed with $400\, mL$ of $0.01 \,M \,H _2 SO _4$. The $pH$ of the mixture is ______$\times 10^{-2}$. (Nearest integer)
[Given $ \log 2 =0.30$
$ \log 3 =0.48 $
$ \log 5 =0.69 $
$ \log 7 -0.84$
$\log 11 =1.04]$

Answer 1

Total milimoles of $ H ^{+} =(600 \times 0.01)+(400 \times 0.01 \times 2)$
$ =14 $
$ {\left[ H ^{+}\right] } =\frac{14}{1000}=14 \times 10^{-3} $
$ pH =3-\log 14 $
$ =1.86 $
$ =186 \times 10^{-2}$