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Q. $6\, g$ of $Mg ( s )$ atoms (atomic mass $=24.0\, amu$ ) is converted into $Mg ^{++}( g )$. Then find the energy required in $kJ\,mol ^{-1}$ for this process, if the first and second ionisation energies of $Mg$ are $740$ and $1440 \,kJ\, mol ^{-1}$, respectively, and enthalpy of sublimation is $100 \,kg\, mol ^{-1}$.

Classification of Elements and Periodicity in Properties

Solution:

Total energy required to convert
$\frac{6}{24}=\frac{1}{4}$ mol of $Mg ( s )$ into $Mg ^{++}$
$E=\frac{1}{4}(100+740+1440)$
$=\frac{2280}{4}=570\, kJ / mol$