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Physics
6. An ideal heat engine gives out heat at 77° C to have a 30 % of efficiency. The temperature of the source is
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Q. 6. An ideal heat engine gives out heat at $77^{\circ} C$ to have a $30 \%$ of efficiency. The temperature of the source is
KCET
KCET 2022
A
$269^{\circ} C$
B
$773^{\circ} C$
C
$673^{\circ} C$
D
$227^{\circ} C$
Solution:
$=1-\frac{T_{2}}{T_{1}}=1-\frac{350}{T_{1}}=0.3$
$0.7 T_{1}=350$
therefore $T_{1}=\frac{350}{0.7}=500 \,K=227^{\circ} C$