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Q. $6.02\times 10^{20}$ molecules of urea are present in $100mL$ solution. The concentration of urea solution is :

NTA AbhyasNTA Abhyas 2020

Solution:

Conc. $=\frac{n_{\text{urea }}}{V \left(\right. L \left.\right)}=\frac{6 . 02 \times \left(10\right)^{20}}{6 . 02 \times \left(10\right)^{23}}\times \frac{1}{0 . 1}$
$=0.01M$