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  4. 500 mL of 0.1 mol HCl has pH

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Q. $500 \,mL$ of $0.1 \,mol \, HCl $ has $pH$

Delhi UMET/DPMTDelhi UMET/DPMT 2007

Solution:

$\left[H^{+}\right]+0.1 / 500 / 1000$
$=\frac{0.1 \times 1000}{500}=0.2$
$p H=-\log \left[H^{+}\right]$
$=-[\log 0.2]=-\log \left[2 \times 10^{-1}\right]$
$=-[\log 2-1 \log 10]$
$=-\log 2+1$
$=-0.3010+1=0.6990$
$\approx 1 .$