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  4. 500 g of water and 100 g of ice at 0°C are in a calorimeter whose water equivalent is 40 g. 10 g of steam at 100° C is added to it. Then water in the calorimeter is: (Latent heat of ice = 80 cal/g, Latent heat of steam =540 cal/g)

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Q. $500 \,g$ of water and $100\, g$ of ice at $0^°C$ are in a calorimeter whose water equivalent is $40\, g$. $10\, g$ of steam at $100^\circ C$ is added to it. Then water in the calorimeter is : (Latent heat of ice $= 80\, cal/g$, Latent heat of steam $=540\, cal/g$)

JEE MainJEE Main 2013Thermal Properties of Matter

Solution:

As $1\,g$ of steam at $100^\circ C$ melts $8g$ of ice at $0^\circ C.$
$10\,g$ of steam will melt $8\times10\, g$ of ice at $0^°C$ Water in calorimeter $= 500 + 80 + 10g = 590g$