1. Tardigrade
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  3. Chemistry
  4. 50 mL of 0.2 M solution of a compound with empirical formula CoCl3.4NH3 on treatment with excess of AgNO3(aq) yields 1.435g of AgCl. Ammonia is not removed by treatment with concentrated H2SO4. How many ionisable chlorine atoms are present in the formula of the compound?

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Q. $50 \,mL$ of $0.2\, M$ solution of a compound with empirical formula $CoCl_{3}.4NH_{3}$ on treatment with excess of $AgNO_{3}\left(aq\right)$ yields $1.435g$ of $AgCl$. Ammonia is not removed by treatment with concentrated $H_{2}SO_{4}$. How many ionisable chlorine atoms are present in the formula of the compound?

Coordination Compounds

Solution:

Moles of $AgCl = \frac{1.435}{143.5} = 0.01 ;50 mL$ of $0.2 M$ complex $= 0.01$ mol
$\left[Co\left(NH_{3}\right)_{4} Cl_{2}\right] Cl\to \left[Co\left(NH_{3}\right)_{4} Cl_{2}\right]^{+} +Cl^{-}$