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  4. 50 mL of 0.1 M CH 3 COOH is being titrated against 0.1 M NaOH. When 25 mL of NaOH has been added, the pH of the solution will be × 10-2 . (Nearest integer) (Given: .pK a ( CH 3 COOH )=4.76) log 2=0.30 log 3=0.48 log 5=0.69 log 7=0.84 log 11=1.04

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Q. $50 \,mL$ of $0.1 \,M \,CH _{3} COOH$ is being titrated against $0.1 \,M\, NaOH$. When $25 \,mL$ of $NaOH$ has been added, the $pH$ of the solution will be _________$\times 10^{-2} .$ (Nearest integer)
(Given : $\left.pK _{ a }\left( CH _{3} COOH \right)=4.76\right)$
$\log 2=0.30$
$\log 3=0.48$
$\log 5=0.69$
$\log 7=0.84$
$\log 11=1.04$

JEE MainJEE Main 2022Equilibrium

Solution:

Moles of $CH _{3} COOH =5\, m$ mole moles of $NaOH =2.5 \,m$ mole
image
so buffer is formed
$ pH = pKa +\log \left(\frac{2.5 / 75}{2.5 / 75}\right)= pKa $
$pH =4.76$
$=476 \times 10^{-2}$