Question

$50 \, g$ of ice at $0 \, ^\circ C$ is mixed with $50 \, g$ of water at $80 \, ^\circ C$ . The final temperature of the mixture is (latent heat of fusion of ice $=80 \, c a l / g$ , $s_{w}=1c a l / g \, ^\circ C$ )

• A. $0^\circ C$
• B. $40 \, ^\circ C$
• C. $60 \, ^\circ C$
• D. less than $0 \, ^\circ C$

Answer 1

Answer: (A)

The heat required by the ice $Q=m\times L=50\times 80=4000 \, cal$
the heat released by water $Q=ms\Delta \theta =50\times 1\times 80=4000 \, cal$
both are equal. Final temperature $=0^\circ C$