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Q. 5 litres of a solution contains 25 mg of $CaCO_3$.What is its concentration in ppm ? (mol. wt. of $CaCO_3\, is\, 100)$

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Solution:

5L dilute solution = 5 kg = 5000 g
Mass of solute = 25 mg = $25 \times 10^{-3}$ g
' ppm of $CaCO_3$ in solution
= $\frac{25}{10^{-3} g}{5000 \, g} \times 10^6$ = 5 ppm.