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  4. 5 g of NaOH was dissolved in deionized water to prepare a 450 mL stock solution. What volume (in mL ) of this solution would be required to prepare 500 mL of 0.1 M solution? Given: Molar Mass of Na, O and H is 23,16 and 1 g mol -1 respectively

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Q. $5 \,g$ of $NaOH$ was dissolved in deionized water to prepare a $450 \,mL$ stock solution. What volume (in $mL$ ) of this solution would be required to prepare $500 \,mL$ of $0.1\, M$ solution?
Given: Molar Mass of $Na, O$ and $H$ is 23,16 and $1 \,g\, mol ^{-1}$ respectively

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Solution:

$ M=\frac{5}{40} \times \frac{1000}{450} $
$ M_1 V_1=M_2 V_2 $
$ \left(\frac{5}{40} \times \frac{1000}{450}\right) \times V_1=0.1 \times 500$
$V_1=180$