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Q.
$5.3 \%$ (W/V) $Na _{2} CO _{3}$ solution and $6.3 \%$ (W/V) $H _{2} C _{2} O _{4} \cdot 2 H _{2} O$ solution have same
Some Basic Concepts of Chemistry
Solution:
$M _{ Na _{2} CO _{3}}=\frac{ w _{ B } \times 1000}{ m _{ B } \times V } $
$M _{ H _{2} C _{2} O _{4} .2 H _{2} O }=\frac{ w _{ B } \times 1000}{ m _{ B } \times V }$
$=\frac{5.3 \times 1000}{106 \times 100}=0.5 $
$=\frac{6.3 \times 1000}{126 \times 1000}=0.5$
$N _{ Na _{2} CO _{3}}=\frac{ w _{ B } \times 1000}{ E _{ B } \times V } $
$N _{ H _{2} C _{2} O _{4} .2 H _{2} O }=\frac{ W _{ B } \times 1000}{ E _{ B } \times V }$
$=\frac{5.3 \times 1000}{53 \times 100}=1 $
$=\frac{6.3 \times 1000}{63 \times 100}=1$