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  4. 5.2 g of polyhydric alcohol was treated with an excess of methyl magnesium bromide to produce 3.36 litre of CH 4 at STP. Calculate number of OH groups present in polyhydric alcohol (molar mass of alcohol =104 g mol -1 )

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Q. $5.2\, g$ of polyhydric alcohol was treated with an excess of methyl magnesium bromide to produce $3.36$ litre of $CH _{4}$ at STP. Calculate number of OH groups present in polyhydric alcohol (molar mass of alcohol $=104\, g\, mol ^{-1}$ )

Alcohols Phenols and Ethers

Solution:

Number of moles of alcohol $=\frac{5.2}{104}=\frac{1}{20}$
Number of moles of $CH _{4}$ produced
$=\frac{3.36}{(22.4\, lt )}=\frac{3}{20}$
So number of $- OH$ groups presents $=3$