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  4. 420 J of energy supplied to 10 g of water will raise its temperature by nearly

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Q. 420 J of energy supplied to 10 g of water will raise its temperature by nearly

Thermal Properties of Matter

Solution:

$ \, \, \, \, Q=mc\Delta \theta$
or $ \, \, \, \, 420 =10 \times 1^{-3} \times (4.2 \times 1000) \Delta \theta$
(Specific heat of water= 4.2 $ \times kJkg^{-1}C^{-1}$
$\Delta \theta =\frac{420}{10 \times 10^{-3}4200}=10^{\circ}C$