Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $400\, mg$ of capsule contains $100 \,mg$ of ferrous fumerate. The percentage of iron present in the capsule is approximately

Some Basic Concepts of Chemistry

Solution:

Mol. mass of $Fe(CHCOO)_{2}=170$
Fe in $100 \,mg$ of $Fe(CHCOO)_{2}=\frac{56 \times 100}{170}$
$=32.9\,mg$
Total Fe in $400\,mg$ of capsule $=32.9\,mg$
$\therefore $ percentage of Fe in capsule
$=\frac{32.9 \times 100}{400}$
$=8.2$