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Q. $40 \%$ (wt./vol.) $NaCl$ has specific gravity $1.12\, g /\, mL$. In ppm the concentration of $NaCl$ is:

Some Basic Concepts of Chemistry

Solution:

$100\, mL$ solution $=100 \times 1.12 \,g$ solution $=112\, g$ solution

That is, $72 \,g\, H _{2} O$ has $40\, g\, NaCl$

$\therefore \frac{40}{72} \times 10^{6}=5.5 \times 10^{5} \,ppm$