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  4. 40 mL of x M KMnO 4 solution is required to react completely with 200 mL of 0.02 M oxalic acid solution in acidic medium. The value of x is

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Q. $40 \,mL$ of $x M KMnO _{4}$ solution is required to react completely with $200\, mL$ of $0.02 \,M$ oxalic acid solution in acidic medium. The value of $x$ is

AP EAMCETAP EAMCET 2016

Solution:

$2 KMnO _{4}+3 H _{2} SO _{4}+5 \underset{\overset{|}{C}OOH}{COOH }\longrightarrow K _{2} SO _{4}+2 MnSO _{4}+8 H _{2} O +10 CO _{2}$

$\because \frac{M_{1} \,V_{1}}{n_{1}}\left( KMnO _{4}\right)=\frac{M_{2} \,V_{2}}{n_{2}}$

image

$ \Rightarrow \frac{x \times 40\, mL }{2}=\frac{0.02 \times 200\, mL }{5}$

$\therefore x=0.04\, M$