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Q. 40 mg of pure sodium hydroxide is dissolved in 10 litres of distilled water. The pH of the solution is

Equilibrium

Solution:

$\left[NaOH\right]=\frac{40\times10^{-3}}{40\times10}=10^{-4} M$
$\left[OH^{-}\right]=10^{-4}M
H^{+}=10^{-10}M$
$pH=10$