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Q. ${ }^{40} K$ isotope of potassium has a half life of $1.37 \times 10^{9}$ years and decays to an isotope of argon which is stable. In a particular sample of moon rock, the ratio of potassium atoms to argon atoms was found to be $1: 7$. The age of the rock, assuming that originally there was no argon present, is

Nuclei

Solution:

$T _{1 / 2}=1.37 \times 10^{9}$ year
Ratio $-$ Potassium : Argon $=1: 7$
Amount of Potassium left $=\frac{1}{8}$
$\left(\frac{1}{2}\right)^{n}=\frac{1}{8}$
$\therefore n$ or number of half lives $=3$