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  4. 40 g of a sample of carbon on combustion left 10% of it unreacted. The volume of oxygen required at STP for this combustion reaction is

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Q. 40 g of a sample of carbon on combustion left 10% of it unreacted. The volume of oxygen required at STP for this combustion reaction is

EAMCETEAMCET 2008

Solution:

$ \underset{12\,g}{\mathop{C}}\,+\underset{22.4\,L}{\mathop{{{O}_{2}}}}\,\xrightarrow{{}}C{{O}_{2}} $ The amount of carbon unreacted $ =40\times \frac{10}{100}g $ $ =4\,g\, $ So, the amount of carbon reacted $ =(40-4)g $ $ =36\,g $ $ \because $ At STP, for the combustion of 12 g of C, oxygen required is = 22.4 L $ \therefore $ For the combustion of 36 g of C, oxygen required will be $ =\frac{22.4}{12}\times 36L=67.2\,L $