1. Tardigrade
  2. Question
  3. Chemistry
  4. 4 I ominus+ Hg 2+ arrow HgI 42- 1 mol each of Hg 2+ and I ominus will form HgI 4 2-

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $4 I ^{\ominus}+ Hg ^{2+} \rightarrow HgI _4^{2-}$
$1$ mol each of $Hg ^{2+}$ and $I ^{\ominus}$ will form $HgI _4{ }^{2-}$

Some Basic Concepts of Chemistry

Solution:

$I ^{\ominus}$ is limiting reagent, so one mole $I ^{\ominus}$ will give $\frac{1}{4}$ mol or $0.25$ mole of $HgI _4{ }^{2-}$