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Q. $4$ grams of an ideal gas occupies $5.6035$ litres of volume at $546 \,K$ and $2 \,atm$ pressure. What is its molecular weight?

States of Matter

Solution:

$M =\frac{ WRT }{ PV }$
$=\frac{4 \times 0.082 \times 546}{2 \times 5.6035}=16$