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  4. 4 g of non-volatile solute dissolved in 36 g of water produces the relative lowering of vapour pressure of 0.1 The molecular mass of the solute is

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Q. 4 g of non-volatile solute dissolved in 36 g of water produces the relative lowering of vapour pressure of 0.1 The molecular mass of the solute is

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Solution:

$\frac{p^{\circ} -p_{s}}{p^{\circ}} =\frac{w_{2} M_{1}}{w_{1}M_{2}}$
$ 0.1= \frac{4 \times18}{36\times M_{2}}$
$ M_{2} = \frac{4\times 18}{36\times 0.1} =20$