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Q. $ 4.6\times {{10}^{22}} $ atoms of an element weigh 13.8 g. The atomic weight of that element is

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Solution:

$ 4.6\times {{10}^{22}} $ atoms weight $ =13.8\,g $ Hence, $ 6.02\times {{10}^{13}} $ atoms will weight $ =\frac{13.8\times 6.02\times {{10}^{23}}}{4.6\times {{10}^{22}}}=180.6g $ (molar mass)