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Q. $ 4.6\times {{10}^{22}} $ atoms of an element weigh $13.8\,g$. The atomic weight of that element is

WBJEEWBJEE 2007

Solution:

$4.6 \times 10^{22}$ atoms weigh $=13.8 g$
Hence,
$6.02 \times 10^{13}$ atoms will weigh
$=\frac{13.8 \times 6.02 \times 10^{23}}{4.6 \times 10^{22}}$
$=180.6 g$ (molar mass)