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Q. 4.5 g of aluminium (at. mass 27u) is deposited at cathode from $ A{{l}^{3+}} $ solution by certain quantity of electric charge. The volume of hydrogen produced at STP from $ {{H}^{+}} $ ions in solution by the same quantity of electric charge will be

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Solution:

From second law of Faraday $ \frac{{{m}_{Al}}}{{{m}_{H}}}=\frac{{{E}_{Al}}}{{{E}_{H}}} $ $ \therefore $ $ \frac{4.5}{{{m}_{H}}}=\frac{27/3}{1} $ or $ {{m}_{H}}=0.5\,g $ $ \because $ The volume of 2 g $ {{H}_{2}} $ at STP = 22.4 L $ \therefore $ The volume of 0.5 g Hz at STP $ =\frac{22.4\times 0.5}{2}L=5.6\,L $