1. Tardigrade
  2. Question
  3. Chemistry
  4. 4.0 moles of argon and 5.0 moles of PCI 5 are introduced into an evacuated flask of 100 litre capacity at 610 K. The system is allowed to equilibrate. At equilibrium, the total pressure of mixture was found to be 6.0 atm. The K p for the reaction is [Given: R =0.082 L atm K -1 mol -1 ]

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. $4.0$ moles of argon and $5.0$ moles of $PCI _{5}$ are introduced into an evacuated flask of $100$ litre capacity at $610 K$. The system is allowed to equilibrate. At equilibrium, the total pressure of mixture was found to be $6.0\, atm$. The $K _{ p }$ for the reaction is [Given : $R =0.082 \, L$ atm $K ^{-1} \, mol ^{-1}$ ]

JEE MainJEE Main 2022Equilibrium

Solution:

$PCl _{5}=5$ mole
$Ar =4$ mole
$P _{\text {Total }}=\frac{9 \times 0.82 \times 610}{100}=4.5\, atm$
$P _{ PCl _{5}}=\frac{5 \times 4.5}{9}=2.5 ; P _{ Ar }=\frac{4 \times 4.5}{9}=2$
image
$P _{\text {total }}=2.5- P + P + P + P _{ Ar }=6$
$P =1.5$
$K _{ p }=\frac{1.5 \times 1.5}{1}=2.25$