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  4. 36 g water and 828 g ethyl alcohol form an ideal solution. The mole fraction of water in it, is:

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Q. 36 g water and 828 g ethyl alcohol form an ideal solution. The mole fraction of water in it, is:

MGIMS WardhaMGIMS Wardha 2003

Solution:

Number of moles of water $ (n)=\frac{36}{18}=2 $ No. of moles of ethyl alcohol $ (N)=\frac{828}{46}=18 $ $ \therefore $ Mole-fraction of water $ =\frac{n}{n+N} $ $ =\frac{2}{2+18}=\frac{2}{20}=0.1 $