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  4. 34.2 g of cane sugar is dissolved in 180 g of water. The relative lowering of vapour pressure will be

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Q. $ 34.2\, g $ of cane sugar is dissolved in $ 180\, g $ of water. The relative lowering of vapour pressure will be

MHT CETMHT CET 2011

Solution:

$\frac{p^{\circ}-p_{S}}{p^{\circ}}=\frac{\frac{w_{2}}{m_{2}}}{\frac{w_{1}}{m_{1}}+\frac{w_{2}}{M_{2}}}$

$= \frac{\frac{34.2}{342}}{\frac{34.2}{342}+\frac{180}{18}}$

$= \frac{0.1}{10.1}$

$ = 0.0099$