Question

$300 \,cal$. of heat is given to a heat engine and it rejects $225\, cal$. of heat. If source temperature is $227^{\circ} C$, then the temperature of sink will be ______${ }^{0} C$.

Answer 1

$1-\frac{ Q _{2}}{ Q _{1}}=1-\frac{ T _{2}}{ T _{1}}$
$\frac{ Q _{2}}{ Q _{1}}=\frac{ T _{2}}{ T _{1}}$
$\frac{225}{300}=\frac{ T _{2}}{500}$
$\frac{500 \times 225}{300}= T _{2}$
$375= T _{2}$
$102^{\circ} C = T _{2}$