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Q. $3.92\,g$ of ferrous ammonium sulphate react completely with $50\, ml \frac{N}{10} KMnO_{4}$ solution. The percentage purity of the sample is

BITSATBITSAT 2014

Solution:

$Eq$ of $KMnO _{4}$ used $=\frac{50 \times 1}{1000 \times 10}=0.005$
$\therefore $ Eq of FAS reacted $=0.005$
$\therefore $ weight of FAS needed
$=0.005 \times 392=1.96\, g$
Thus percentage purity of FAS is $50 \%$