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Chemistry
3.92 g of ferrous ammonium sulphate react completely with 50 ml (N/10) KMnO4 solution. The percentage purity of the sample is
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Q. $3.92\,g$ of ferrous ammonium sulphate react completely with $50\, ml \frac{N}{10} KMnO_{4}$ solution. The percentage purity of the sample is
BITSAT
BITSAT 2014
A
50
76%
B
78.4
12%
C
80
12%
D
39.2
0%
Solution:
$Eq$ of $KMnO _{4}$ used $=\frac{50 \times 1}{1000 \times 10}=0.005$
$\therefore $ Eq of FAS reacted $=0.005$
$\therefore $ weight of FAS needed
$=0.005 \times 392=1.96\, g$
Thus percentage purity of FAS is $50 \%$