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  4. 3.9 g of a mixture of aluminium and its oxide on reaction with aqueous solution of sodium hydroxide, gave 840 mL of a gas under standard conditions. Thus, aluminium content in the mixture is

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Q. $3.9\, g$ of a mixture of aluminium and its oxide on reaction with aqueous solution of sodium hydroxide, gave $840 \,mL$ of a gas under standard conditions. Thus, aluminium content in the mixture is

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Solution:

$Al + NaOH + H _2 O \rightarrow NaAlO _2+1.5 H _2$
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$33.6\, L\, H _2$ gas are from $=27\, g \,Al$
$0.840\, L\, H _2$ gas are from $=\frac{27 \times 0.840}{33.6} g \,Al$
$=0.675\, g \,Al$