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Q. $\sqrt{-3}\sqrt{-6}$ is equal to

Complex Numbers and Quadratic Equations

Solution:

$\sqrt{-3}=i\sqrt{3}$,
$\sqrt{-6}=i\sqrt{6}$
So, $\sqrt{\left(-3\right)}\sqrt{\left(-6\right)}$
$=i^{2} \,3\sqrt{2}$
$=-3\sqrt{2}$