Question

$3.6$ gram of oxygen is adsorbed on $1.2\, g$ of metal powder. What volume of oxygen adsorbed per gram of the adsorbent at $1\,atm$ and $273 \,K$ ?

• A. $0.19\, Lg ^{-1}$
• B. $1\, Lg ^{-1}$
• C. $2.1\, Lg ^{-1}$
• D. None of these

Answer 1

Answer: (C)

Mass of oxygen adsorbed per gram of metal powder
$=\frac{3.6}{1.2} g =3\, g = m$ B
y ideal gas equation, $P V=n R T$
$\therefore V=\frac{ mRT }{ MP }=\frac{3 \times 273 \times 0.0821}{32 \times 1 atm }$
$=2.1\, Lg ^{-1}$