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Q. $3.2$ moles of hydrogen iodide was heated in a sealed bulb at $444°C$ till the equilibrium state was reached. Its degree of dissociation at this temperature was found to be $22\%$. The number of moles of hydrogen iodide present at equilibrium is

Equilibrium

Solution:

$\frac{22}{100} \times 3.2 =0.704$
$\therefore $ at equil. moles of $HI = 3.2 - 0.704 = 2.496$