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Q. $3.0\, g$ of a salt of molecular weight $30$ is dissolved in $250 \,g $ water. The molarity of the solution is ............

IIT JEEIIT JEE 1983Some Basic Concepts of Chemistry

Solution:

Molarity $=\frac{\text { Number of moles of solute }}{\text { Volume of solution in litre }} $
$=\frac{\text { Weight of solute }}{\text { Molar mass }} \times \frac{1000}{\text { Volume in mL }}$
$=\frac{3}{30} \times \frac{1000}{250}=0.4\, M$