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Q.
$3.0\, g$ of a salt of molecular weight $30$ is dissolved in $250 \,g
$ water. The molarity of the solution is ............
IIT JEEIIT JEE 1983Some Basic Concepts of Chemistry
Solution:
Molarity $=\frac{\text { Number of moles of solute }}{\text { Volume of solution in litre }} $
$=\frac{\text { Weight of solute }}{\text { Molar mass }} \times \frac{1000}{\text { Volume in mL }}$
$=\frac{3}{30} \times \frac{1000}{250}=0.4\, M$