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  4. 2 HCHO xrightarrow50 % NaOH CH 3 OH + HCOONa This reaction is called:

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Q. $2 HCHO \xrightarrow{50 \% NaOH } CH _{3} OH + HCOONa$ This reaction is called:

Jharkhand CECEJharkhand CECE 2003

Solution:

Define all reactions to find correct answer.
(i) Aldol condensation: carbonyl compound which have
$\alpha-H$ atom $+N a O H \rightarrow \beta$ - hydroxy carbonyl compound
(ii) Reimer Tiemann reaction:
Phenol $+ CCl _{4}+ NaOH \rightarrow$ Salicylic acid
(iii) cannizaro reaction:
$\underset{\text{which do not have $\alpha- H$ atom}}{\text{Aldehyde}} + NaOH \rightarrow$ alcohol + acid .,
$\underset{\text { formalehyde }}{2 HCHO } \xrightarrow{50} \underset{\text { methanal }}{ CH _{3} OH }+\underset{\text { sodium formate }}{ HCOONa }$