1. Tardigrade
  2. Question
  3. Chemistry
  4. 2.0 g of oxygen contains number of atoms equal to that in

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. 2.0 g of oxygen contains number of atoms equal to that in

JIPMERJIPMER 2014Some Basic Concepts of Chemistry

Solution:

Number of atoms in 1 g of an element
$= \frac{6.023 \times 10^{23}}{at.mass}$
$\therefore $ Number of atoms in 2 g of oxygen
$= \frac{6.023 \times 10^{23}}{16} \times 2 = \frac{6.023 \times 10^{23}}{8}$
Now, number of atoms in 4 g of sulphur
$= \frac{6.023 \times 10^{23}}{32} \times 4 = \frac{6.023 \times 10^{23}}{8}$