1. Tardigrade
  2. Question
  3. Physics
  4. 27 mercury drops coalesce to form one mercury drop, the energy changes by a factor of

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. 27 mercury drops coalesce to form one mercury drop, the energy changes by a factor of

Mechanical Properties of Fluids

Solution:

$R = n ^{1 / 3} r $
$\Rightarrow R =3 r$
$\frac{\text { Energy of big drop }}{\text { Energy of small drop }}=\frac{ T \times 4 \pi R ^{2}}{ T \times 4 \pi r ^{2}}$
$\frac{R^{2}}{r^{2}}=\frac{(3 r)^{2}}{r^{2}}=9$