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Q. $27 g$ of $Al$ will react completely with how many grams of oxygen?

Some Basic Concepts of Chemistry

Solution:

$4Al + 3O_2\to2Al_2O_3$
$At. Wt. of Al = 27$
Thus $4 \times 27 g$ of $Al$ reacts with oxygen $= 3 \times 32 g$
$\therefore 27 g$ of $Al$ reacts with oxygen$ = \frac{3\times32}{4\times27}\times27=24 g$