1. Tardigrade
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  3. Chemistry
  4. 2713AI is a stable isotope, 2913AI is expected to decay by

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Q. $^{27}_{13}AI$ is a stable isotope, $^{29}_{13}AI$ is expected to decay by

IIT JEEIIT JEE 1996

Solution:

$^{}_{13}AI^{29}$ is neutron rich isotope, will decay by
$\beta$-emission converting some of its neutron into
proton as
$ ^{}_{0}n^1 \longrightarrow \, \,{}^{}_{-1}\beta^0 + \,{}^{}_{1}H^1$