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Q. $26$ tuning fork are arranged in a line having beat frequency of $4$ between two successive tuning forks. If frequency of last tuning fork is $3$ times that of $1\text{st}$ tuning fork then find the frequency of 1st tuning fork:

Rajasthan PMTRajasthan PMT 2002Waves

Solution:

Beat fréquency of two successive tuning forks is $4$
$\therefore $ difference between the frequencies $=4$
From formula of $A.P.$
$ l =a+(n-1) d $
$3 f =f+(26-1) \times 4 $
$2 f =100 $
$ f =50 \,Hz $