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  4. 26.65gm of compound having formula ([Cr (H2 O)5 Cl)](Cl)2⋅ H2O is mixed with 498.2gm water. If complex is 75 % ionised in water, then elevation in boiling point in Kelvin for above solution is X . Calculate 4X ? ( k b . water =0.50 k kg mol -1 ) (At. wt. .Cr: 52, Cl: 35.5, O: 16)

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Q. $26.65gm$ of compound having formula $\left(\left[Cr \left(H_{2} O\right)_{5} Cl\right)\right]\left(Cl\right)_{2}\cdot H_{2}O$ is mixed with $498.2gm$ water. If complex is $75\%$ ionised in water, then elevation in boiling point in Kelvin for above solution is $X$ . Calculate $4X$ ?
$\left( k _{ b }\right.$ water $=0.50 k \quad kg mol -1$ ) (At. wt. $\left.Cr : 52, Cl : 35.5, O : 16\right)$

NTA AbhyasNTA Abhyas 2022

Solution:

$\frac{26.65}{266.5}=0.1$ mole
Total water $=498.2+18=500 gm$
$ \begin{array}{l} \Delta T _{ b }= imk _{ b }=\left(1+2 \times \frac{3}{4}\right) \frac{0.1}{0.5} \times 0.5 \\ =0.254 X =4 \times 0.25=1 \end{array} $