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Q. $250\, ml$ of a sodium carbonate solution contains $2.65$ grams of $Na_2CO_3$. If $10\, ml$ of this solution is diluted to one litre, what is the concentration of the resultant solution (mol. wt. of $Na_2CO_3 = 106)$

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Solution:

Molarity $ = \frac{W(g) \times 1000}{\text{molecular wt.} \times V(ml.)}$
$ = \frac{2.65 \times 1000}{106 \times 250} = 0.1 \,M$
$10$ ml of this solution is diluted to $1000$ ml $N_1 V_1 = N_2V_2$
$10 \times 0.1 = 1000 \times x$
$x = \frac{0.1 \times 10}{1000} = 0.001\,M$