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Q. 25 mL of a solution of barium hydroxide on titration with a 0.1 molar solution of hydrochloric acid gave a titre value of 35 mL. The molarity of barium hydroxide solution was

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Solution:

$Ba ( OH )_2+2 HCl \longrightarrow BaCl _2+2 H _2 O$
$\frac{M_1 V_1}{n_1}=\frac{M_2 V_2}{r_2}$
${\left[ Ba ( OH )_2\right][H C l] }$
$\frac{M_1 \times 25}{1}=\frac{0.1 \times 35}{2}$
$M_1=\frac{0.1 \times 35}{2 \times 25}=0.07 M$