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  4. 25 mL of 0.08 N Mohr's salt solution is oxidised by 20 mL of K2Cr2O7 in acidic medium. The mass of Mohr's salt present in 500 cc is

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Q. 25 mL of 0.08 N Mohr's salt solution is oxidised by 20 mL of $K_2Cr_2O_7$ in acidic medium. The mass of Mohr's salt present in 500 cc is

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Solution:

0.08 N of Mohr's salt= 0.08 M
No. of moles in 25 mL of 0.08 M Mohr's salt solution
$ = 0.08 \times \frac{25}{1000} = 0.002$
No. of moles in 500 cc of Mohr's salt solution
$ 0.002 \times \frac{500}{25} = 0.04$
Hence, mass of Mohr's salt present in 500 cc
$ = 0.04 \times 392 = 15.68 g$