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  4. 25 mL, 0.2 M Ca(OH)2 is neutralised by 10 mL of 1 M HCI. Then pH of resulting solution is

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Q. 25 mL, 0.2 M Ca(OH)2 is neutralised by 10 mL of 1 M HCI. Then pH of resulting solution is

AIIMSAIIMS 2011Equilibrium

Solution:

Number of millimoles of base (i.e., $Ca(OH)_{2})$

$N_1V_1=2 \times M_{1} \times V_{1} =2 \times 0.2 \times 25=10$

Number of millimoles of acid (i, e,, $HCl)=N_{2} V_{2} =10 \times 1=10$

As . no. of millimoles of acid = no. of millimoles of base

$\therefore $ Acid is completely neutralised by base forming a neutral solution.

$\therefore pH$ of the resulting solution $=7$