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  4. 23 g of sodium shall react with methyl alcohol (CH3OH), to give

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Q. $23 \,g$ of sodium shall react with methyl alcohol $(CH_3OH)$, to give

Alcohols Phenols and Ethers

Solution:

$23\, g$ of $Na \equiv 1$ mole of $Na$
$CH_3OH + Na \rightarrow CH_3ONa + \frac{1}{2} H_2 \uparrow$