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Q. $20$ persons are setting in a particular arrangement around a circular table. Three persons are to be selected for leaders. The number of ways of selection of three persons such that no two were sitting adjacent to each other is

Permutations and Combinations

Solution:

Total ways of selection without restriction $={ }^{20} C_{3}$
Number of ways of selection when two are adjacent
$=20 \times{ }^{16} C_{1}$
Number of ways of selection when all the three are adjacent $=20$.
Required number of ways $={ }^{20} C_{3}-20 \times 16-20$
$=\frac{20 \times 19 \times 18}{6}-20 \times 16-20=20[57-16-1] $
$=20 \times 40=800$